Answer:
After the reflection over the line y = -x, the image of the point is: (-3,-2)
Step-by-step explanation:
When a given point is reflected over a line the point only changes place but the distance between the point and the line remains same.
Let (x,y) be a point on the plane
and
y = -x be a line on the plane
When a point is reflected over a line y = -x , the coordinates of the point are exchanged which means x becomes y and y becomes x and both are negated
So (x,y) will become (-y,-x)
Given point is:
(2,3)
After the reflection over the line y = -x, the image of the point is: (-3,-2)
I don't know i just want some points
Step-by-step explanation:
well thank you anyways hope someone else can help you i am sorry.
Answer: Equation that represents this situation is 5(x+17) = 1495,
Price of one ticket is 282
Step-by-step explanation:
Here x represents the price of one ticket,
Also, a person bought travel insurance that costs $17 per ticket.
Hence, the total cost of a person = x + 17
⇒ The total cost of 5 person = 5 ( x + 17 )
But, According to the question,
5 ( x + 17 ) = 1495
⇒ x + 17 = 299
⇒ x = 299 - 17
⇒ x = 282
Hence, the price of one ticket = $ 282
2x -8 that’s how u write it in an expression
Answer:

Step-by-step explanation:
* Lets explain how to solve the problem
- The rule of expand the binomial is:

∵ The binomial is 
∴ a = 10k , b = -m and n = 5
∴ 
∵ 5C1 = 5
∵ 5C2 = 10
∵ 5C3 = 10
∵ 5C4 = 5
∵ 5C5 = 1
∴ 
∴ 