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siniylev [52]
3 years ago
14

You read 9.75 pages in your science book and 24.5 pages of a play for English class. It takes you 1.2 minutes to read each page

of science and 0.8 of a minute to read each page of the play. How much time do you spend reading?
CLEAR CHECK
Mathematics
2 answers:
Kazeer [188]3 years ago
7 0

Answer:

31.3 minutes were spent reading

Step-by-step explanation:

If it takes 1.2 minutes to read each page for science and you read 9.75 pages of science, then you must multiply these two numbers together

9.75 pages × 1.2 mins = 11.7

If it takes 0.8 of a minute to read each page of the play and you read 24.5 pages of a play, then you also multiplying these two numbers

24.5 pages × 0.8 mins = 19.6

If we must find out the time spent reading, we must add these two numbers together

11.7 + 19.6 = 31.3

Vesnalui [34]3 years ago
4 0
Yous pent 31.3 minutes reading....
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Step-by-step explanation:

a) y' -4y = -8

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We have to find the eigenvalues of this differential equation, which are the roots of this equation:

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Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

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The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

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b) y' +4y = 8

The first step is finding y_{n}(t). So:

y' + 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r + 4 =

r = -4

So:

y_{n}(t) = y_{0}e^{-4t}

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' +4(y_{p}) = 8

(C)' + 4C = 8

C is a constant, so (C)' = 0.

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{-4t} + 2

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Step-by-step explanation:

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