Answer:
paul will spend 33
Step-by-step explanation:
66-43
Answer:
1st one
Step-by-step explanation:
X = 4 y = 3 4x-3y=7 x=13-3y
4(13-3y) -3y =7
52 -12y -3y =7
-15y=-45
-y=-3 y = 3
x=13-(3*3)
x=13-9
x =4
Answer:
P(57 < X < 69) = 0.1513
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 45, \sigma = 14](https://tex.z-dn.net/?f=%5Cmu%20%3D%2045%2C%20%5Csigma%20%3D%2014)
Find P(57 < X < 69):
This is the pvalue of Z when X = 69 subtracted by the pvalue of Z when X = 57. So
X = 69
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{69 - 45}{14}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B69%20-%2045%7D%7B14%7D)
![Z = 1.71](https://tex.z-dn.net/?f=Z%20%3D%201.71)
has a pvalue of 0.9564
X = 57
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{57 - 45}{14}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B57%20-%2045%7D%7B14%7D)
![Z = 0.86](https://tex.z-dn.net/?f=Z%20%3D%200.86)
has a pvalue of 0.8051
0.9564 - 0.8051 = 0.1513
P(57 < X < 69) = 0.1513