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Margaret [11]
2 years ago
10

Need some help with this question in the imageCheers​

Mathematics
1 answer:
iren [92.7K]2 years ago
5 0

Step-by-step explanation:

a) 24.7×52.3=1291.81

On rounding off to 3 significant digits we get

1290

b)

\sqrt{ {42}^{2} -  {28}^{2}  }

\sqrt{1764 -784 }  =  \sqrt{980}

=31.304951

On rounding off to 5 significant figures we get

=31.305

c)

\sqrt[3]{78}  = 4.27265

On rounding off to 2 significant figures we get

=4.3

Hence required answers

a)1290

b)31.305

c)4.3

I hope it helped you

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The equation of the line passing through the points (−10, 0) and (−8, 20) can be expressed as y = mx + b. Give the value of b.
weeeeeb [17]

Given are the two points (-10,0) and (-8,20), and equation of the line as y=mx+b.

We can plug the given values in the equation as follows :-

0 = -10m + b .........equation(1)

20 = -8m + b .........equation(2)

Subtracting equation(1) from equation(2)

20 - 0 = (-8m + b) - (-10m + b)

20 = -8m + b + 10m - b

20 = 10m - 8m

20 = 2m

m = 10

Plugging m=10 in the equation(1)

0 = -10(10) + b

0 = -100 + b

b = 100

So final answer is b = 100.

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3 years ago
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Nikitich [7]

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3 years ago
What is the equation of the line that passes through the point (6, 8) and has a slope 1/2
Korvikt [17]

Answer:

y=1/2x+5

Step-by-step explanation:

Plug it into the formula for a point and a slope.

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Y-8=1/2(x-6)

Then multiply the 1/2 to the x and -6. After you do that, move everything so that it has y by itself on the left. Your ending should be y=1/2x+5.

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The metric designators and trade sizes are for identification purposes only and are not actual dimensions, as pointed out in the
Basile [38]

The metric designators and trade sizes are for identification purposes only and are not actual dimensions, as pointed out in the note in table 300.1(C).

<h3>What are identification purposes?</h3>
  • For identification purposes, an acceptable ID MUST be issued by a Federal, State, County, or Municipal entity.
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[Refer The table 300.1(C) below.]

Therefore, the metric designators and trade sizes are for identification purposes only and are not actual dimensions, as pointed out in the note in table 300.1(C).

Know more about identification purposes here:

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The correct question is given below:

The metric designators and trade sizes are for identification purposes only and are not actual dimensions as pointed out in the note to Table?

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What is the expression of g(x) when we perform the following sequence of transformations onto the parent function fx=x2:
astraxan [27]

The expression of function g(x) is (\frac x2 - 1)^2

<h3>How to determine the expression?</h3>

The function is given as:

f(x) = x^2

When the function is shifted right by 1 unit, the rule is:

f'(x) = f(x - 1)

So, we have:

f(x) = (x - 1)^2

When the function is compressed horizontally by a factor of 2, the rule is:

f'(x) = f(x/2)

So, we have:

g(x) = (\frac x2 - 1)^2

Hence, the expression of function g(x) is (\frac x2 - 1)^2

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