3x + 2y = 10 ....multiply by -4
12x + 5y = 25
-------------------
-12x - 8y = -40 (result of multiplying by -4)
12x + 5y = 25
------------------add
-3y = - 15
y = -15/-3
y = 5
3x + 2y = 10
3x + 2(5) = 10
3x + 10 = 10
3x = 10 - 10
3x = 0
x = 0
solution is (0,5)
Square and Rhombus are the following quadrilaterals have diagonals that are always perpendicular to each other.
C. Square
D. Rhombus
<u>Step-by-step explanation:</u>
This implies the diagonals of a square and rhombus are perpendicular. The diagonals of a square and rhombus are a similar length. In elementary geometry, the property of being opposite is the connection between two lines which meet at a right angle. The property stretches out to other related geometric items.
Principally Perpendicular lines will be lines that cross at a right (90 degrees) edge. so when it goes under shape rhombus and square have the equivalent of a considerable number of sides parallelly.
Answer:
For this type of question you might want to give a domain in a set statement
ie.24 is less than 2(13,14,15,...)
<em><u>Or</u></em>
<em>If</em><em> </em><em>my</em><em> </em><em>fi</em><em>rst</em><em> </em><em>answer</em><em> </em><em>was</em><em> </em><em>a</em><em> </em><em>deviation</em><em> </em><em>then</em><em> </em><em> you</em><em> </em><em>were</em><em> </em><em>proba</em><em>bly</em><em> </em><em>being</em><em> </em><em>ask</em><em>ed</em><em> to</em><em> </em><em>subt</em><em>ract</em><em> </em><em>2</em><em>4</em><em> </em><em>fro</em><em>m</em><em> </em><em>2</em><em>t</em><em>i</em><em>m</em><em>e</em><em>s</em><em> </em><em>a</em><em> </em><em>giv</em><em>en</em><em> </em><em>num</em><em>ber</em><em> </em><em>being</em><em> </em><em>repres</em><em>e</em><em>nted</em><em> </em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>varia</em><em>ble</em><em> </em><em>x</em>
I think the answer is 2 2/5
