Answer:
(see below)
Step-by-step explanation:
First, to make it easier for yourself, "flip" the triangles so that they "match." To see what I'm talking about, refer to IMAGE.A.
Now that you can tell that the congruent side and angles are corresponding, you have to prove them congruent.
There is one side and two angles, so it's AAS or SAA.
Answer: 0 in the 1-20 range, 1 in the 21-40 range, 3 in the 41-60 range, 2 in the 61-80 range, and 2 in the 81-100 range.
Explanation:
No change, 0 in the 1-20 range
33: 1 in the 21-40 range
43, 44, 52: 3 in the 41-60 range
75, 79: 2 in the 61-80 range
86, 89: 2 in the 81-100 range.
Answer:
-sinx
Step-by-step explanation:
a trig identity that is crucial to solving this problem is: sin^2 + cos^2 = 1
with knowing that, you can manipulate that and turn it into 1 - sin^2x = cos^x
so 1-sin^2x/sinx - cscx becomes cos^2x/sinx - cscx
it is also important to know that cscx is the same thing as 1/sinx
knowing this information, cscx can be replaced with 1/sinx
(cos^2x)/(sinx - 1/sinx)
now sinx and 1/sinx do not have the same denominator, so we need to multiply top and bottom of sinx by sinx; it becomes....
cos^2x
---------------------
(sin^2x - 1)/sinx
notice how in the denominator it has sin^2x-1 which is equal to -cos^2x
so now it becomes:
cos^2x
--------------
-cos^2x/sinx
because we have a fraction over a fraction, we need to flip it
cos^2x sinx
---------- * ----------------
1 - cos^2x
because the cos^2x can cancel out, it becomes 1
now the answer is -sinx
Answer:
Yes, because when the side lengths of a triangle are in the ratio 3: 4: 5, then it is a right triangle. These sides are 6: 8: 10, then the triangle is a right one.
Step-by-step explanation:
