What are the first five common multiples of five and six

Find a number if: 3/7 of it is 2 1/4

Sergeeva-Olga [200]

Answer:

x=5 1/4

Step-by-step explanation:

2 1/4= $\frac{9}{4}$ ---> $\frac{9}{4}$ divided by 3 to find 1/7x----> $\frac{3}{4}$ =1/7x---> x=21/4---> x=5 1/4

8 0

3 years ago

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A random sample of 16 students selected from the student body of a large university had an average age of 25 years and a populat

eimsori [14]

Answer:

$t=\frac{25-24}{\frac{2}{\sqrt{16}}}=2$

$p_v =P(t_{15}>2)=0.0320$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean is significant higher than 24 years.

Step-by-step explanation:

1) Data given and notation

$\bar X=25$ represent the sample mean

$s=2$ represent the standard deviation for the sample

$n=16$ sample size

$\mu_o =24$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Confidence =0.95 or 95%

$\alpha=0.05$

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean is higher than 24, the system of hypothesis would be:

Null hypothesis: $\mu \leq 24$

Alternative hypothesis: $\mu > 24$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{25-24}{\frac{2}{\sqrt{16}}}=2$

Calculate the P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>2)=0.0320$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean is significant higher than 24 years.

3 0

3 years ago

PLEASE HELP ASAP!!

sesenic [268]

$f(x) = {(x + \frac{b}{2})}^{2} + \frac{24 - b}{2}$

8 0

3 years ago

Good Treads and Speed Tracks manufacture tires. Good Treads claims that their tires last longer than Speed Tracks tires. A car c

Crazy boy [7]

The answer is B... good treads claim is false therefore it can be concluded that speed tracks tires last longer than good treads tires

3 0

3 years ago

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An assembly line with 10 tasks needs be designed. The total time for all tasks is 16 minutes. If you need to produce 30 units/ho

Sindrei [870]

Answer: 8 minimum work stations is what would be needed.

Step-by-step explanation:

The cycle time is computed as the operating time daily divided by the scheduled output.

It is important to note that the daily capacity of the operation layout is the operating time divided by the cycle time.

Therefore,

If you need to produce 30units/hour.

The average cycle time is as follow:

The average cycle time is the average time between the completions of units.

60/30= 2 average cycle time

=16/2

=8

8 work stations is the minimum number that would be needed.

It is important to know that in an assembly line balancing, the minimum number of work station is the ratio of the sum of all tasks time to the cycle time.

5 0

3 years ago