To start, combine each like-term on each side of the equal sign (The numbers with variables in-common // the numbers alike on the same side of the equal sign):
-7x + 6 = 12 - 5x
Now, we get the two terms with variables attached to them, on the same side, so, we do the opposite of subtraction, which is, addition:
So, the answer is 'B.' _________________________________________
3.) 4x + 6 - 3x = 12 - 2x - 3x
Again, we combine the like-terms, on both sides of the equal sign:
x + 6 = 12 - 5x
Now, we get both terms with the variable 'x,' to the same side, and, the opposite of subtraction, is addition, so, we're going to add 5x to both sides:
Yes, a GPA of 3.8 is more than one standard deviation from the mean
Step-by-step explanation:
Let <em>X</em> = student's college GPA.
The random variable <em>X</em> follows a Norma distribution (since it is uni-modal and symmetric) with parameter <em>μ</em> = 2.7 and <em>σ</em> = 0.5.
To determine whether a GPA of 3.8 is more than one standard deviation from the mean, compute the percentile ranks of each GPA.
Compute the probability of getting a GPA less than 3.8 as follows:
*Use a <em>z</em>-table for the probability.
The GPA of 3.8 is at the 99th percentile.
Compute the probability of getting a GPA less than (μ + σ) as follows:
*Use a <em>z</em>-table for the probability.
The GPA of (μ + σ =) 3.2 is at the 84th percentile.
Since the percentile rank of GPA 3.8 is more than the percentile rank of GPA 3.2, i.e. one standard deviation from the mean, it can be concluded that a GPA of 3.8 is more than one standard deviation from the mean.
We can start by finding angle y, which is supplementary to 160.
180-160=20
angle y = 20 degrees.
With that, we can find angle w using the interior-exterior sangle theorem (or whatever name you use for it) which states that "the measure of an exterior angle of a triangle equals the sum of the measures of two remote interior angles". In other words:
