Answer:
6.6
Step-by-step explanation:
brainliest
its me from the last question
Given that the number of bridges has been modeled by the function:
<span>y=149(x+1.5)^2+489,505
To find the year in which, y=505000 we shall proceed as follows:
From:
</span>y=149(x+1.5)^2+489,505
substituting y=505000 we shall have:
505000=149(x+1.5)^2+489,505
simplifying the above we get:
0=149(x+1.5)^2-15495
expanding the above we get:
0=149x^2+447x+335.25-15495
simplifying
0=149x^2+447x-15159.8
solving the quadratic equation by quadratic formula we get:
x~8.69771 or x~-11.6977
hence we take positve number:
x~8.69771~8.7 years~9 years
thus the year in which the number will be 505000 will be:
2000+9=2009
Answer:
The finance charge is 23,028
Step-by-step explanation:
I think you just are supposed to just add and multiply in this case
Answer:
x=6,-6
Step-by-step explanation:
![x^{2} -36=0\\Square root [tex]x^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-36%3D0%5C%5C%3C%2Fp%3E%3Cp%3ESquare%20root%20%5Btex%5Dx%5E%7B2%7D)
and 36
(x+6)(x-6)=0\\
x=6,-6[/tex]\\
Add or Mulitaply or divoin that is really the main thing you have to do
Step-by-step explanation:
