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3 years ago

10

16 cm to 44.2 cm increase or decrease

2 answers:

Delvig [45]3 years ago

6 0

Answer:

Increase.

Step-by-step explanation:

44.2cm is a higher number than 16cm.

Assoli18 [71]3 years ago

3 0

Answer:

Increase

Step-by-step explanation:

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Please help me quick I’ll give brainliest

Anarel [89]

I think c!!!!!!!!!!!!!!!!!!!!

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3 years ago

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30 POINTS For Answers To Questions 1-10

DochEvi [55]

QUESTION 1

The angle $33x+3$ and $135\degree$ are alternate exterior angles.

Since alternate interior angles are congruent, we must have;

$33x+3=135\degree$

Group similar terms.

$\Rightarrow 33x=135-3$

$\Rightarrow 33x=132$

QUESTION 10

We solve the following equation for the two alternate exterior angles to find x.

$x+134=130$

$\Rightarrow x=130-134$

$\Rightarrow x=-4$

$\Rightarrow x=\frac{132}{33}$

$\Rightarrow x=4$ .

QUESTION 2

The angle $120\degree$ and $31x-4$ degree angle are alternate interior angles.

Alternate interior angles are also equal

$\Rightarrow 31x-4=120\degree$

$\Rightarrow 31x=120+4$

$\Rightarrow 31x=124$

$\Rightarrow x=\frac{124}{31}$

$\Rightarrow x=4$

QUESTION 3

The angle $120\degree$ and $x+124$ degree angle are alternate interior angles.

Alternate interior angles are congruent

$\Rightarrow x+124=120\degree$

$\Rightarrow x=120-124$

$\Rightarrow x=-4$

QUESTION 4

The given angles, $40x+5$ and $42x-1$ are alternate interior angles.

$\Rightarrow 40x+5=42x-1$

Group like terms;

$\Rightarrow 5+1=42x-40x$

$\Rightarrow 6=2x$

Divide both sides by 2 to get;

$\Rightarrow x=3$

QUESTION 5

The given angles, $20x+4$ and $19x+9$ are alternate interior angles.

$\Rightarrow 20x+4=19x+9$

Group like terms;

$\Rightarrow 20x-19x=9-4$

$\Rightarrow x=5$

QUESTION 6

The given angles, $11x$ and $-9+12x$ are alternate exterior angles.

Since the alternate exterior angles are congruent, we have;

$-9+12x=11x$

We group similar terms to obtain;

$12x-11x=9$

$\Rightarrow x=9$

QUESTION 7

The two angles, $x+88$ and $80$ .

The two alternate interior angles are congruent.

$\Rightarrow x+88=80\degree$

$\Rightarrow x=80-88$

$\Rightarrow x=-8$

QUESTION 9

The two angle alternate interior angles.

These angles are congruent.

This implies that;

$x+75=70$

$\Rightarrow x=70-75$

$\Rightarrow x=-5$

QUESTION 10

We solve the following equation for the two alternate exterior angles.

$x+134=130$

$\Rightarrow x=130-134$

$\Rightarrow x=-4$

6 0

3 years ago

A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other w

hoa [83]

Answer:

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

Step-by-step explanation:

Volume of cylinder = V

Radius of cylinder = r = 0.5 m

Height of the cylinder = 5 m

Volume of cylinder = $\pi r^2h$

$V=3.14\times (0.5 m)^2\times 5 =3.925 m^3$

Mass of gasoline = m

Density of gasoline = d = $673 kg/m^3$

$m=d\times V=673 kg/m^3\times 3.925 m^3=2,641.525 kg$

Work done to pump the gasoline out of the tank W

Acceleration due to gravity = g $.8 m/s^2$

The center of gravity of fuel in fully filled tank will be centre so, the value of h = 2 m + 0.5 m = 2.5 m

$W =m\times g\times h$

$W=2,641.525 kg\times 9.8 m/s^2\times 2.5 m=64,717.36 J$

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

6 0

3 years ago

Alexis and Tasha challenged each other to a

Anvisha [2.4K]

Answer:

45 WPM

Step-by-step explanation:

A = 1.2T

54 = 1.2T

T = 45

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3 years ago

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Find the quotient −12.73 /−1.9

BlackZzzverrR [31]

The answer would be 6.7

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3 years ago