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stepan [7]
3 years ago
10

16 cm to 44.2 cm increase or decrease ​

Mathematics
2 answers:
Delvig [45]3 years ago
6 0

Answer:

Increase.

Step-by-step explanation:

44.2cm is a higher number than 16cm.

Assoli18 [71]3 years ago
3 0

Answer:

Increase

Step-by-step explanation:

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1 cat + 20 dogs + 60 men + 5 shark=​
Goryan [66]

Answer:

Step-by-step explanation:

1 cat + 20 dogs + 60 men + 5 shark=​ 86

6 0
3 years ago
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Which inequality is shown in the graph?
masha68 [24]

Answer:

D.

Step-by-step explanation:

the graph has a y intercept of -3

try substituting any point in one of the equations that fit the graph in this one that is D.

try(1,1)

1<1-3

1<-3

it is false so shade the outside of the graph

hope it helps

7 0
3 years ago
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A square has a perimeter of 40cm what is the length of each side​
docker41 [41]

Answer:

length of each side : 10 cm

Step-by-step explanation:

all sides of squares are equal

thus, 4 sides = 40 cm

1 side = 40/10 cm

1 side = 10 cm

5 0
2 years ago
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BRAINLIEST AND MAX PTS<br><br> CONVERT y = 40x + 600 to point-slope form
IRISSAK [1]

Answer:

The answer to your question is y - 0 = 40(x - 15)

Step-by-step explanation:

                                  y = 40x + 600

Convert to                 y - y₁ = m(x - x₁)          

Process

1.- Factor 40 in the right side of the equation

                                 y = 40(x - 15)

2.- Give the form of the point slope form

                                 y - 0 = 40(x - 15)

where

y₁ = 0

m = 40

x₁ = 15

3 0
3 years ago
Read 2 more answers
There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con
grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

\square ABCD

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD

\angle BAC = \angle  DCA

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC

and

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED

So, the congruent sides and angles of △ABE and △CDE are:

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD ---- S

\angle BAC = \angle  DCA ---- A

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED or \[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC  --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0
2 years ago
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