The 12 sided cube with the numbers 1 to 12 is rolled. That means it can land on any number from 1 to 12. The number of total possible outcomes is 12. The number of favourable outcomes, that is, the number of times the cube lands on a number than 4 is 12-1=11.
Probability=Number of favourable outcomes/number of total possible outcomes
= 11/12
= 0.92
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Answer:
Step-by-step explanation:
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<span>Lets say the 1st die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
2,1
2,2
Now say the 2nd die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
1,2
2,2
Now we want to count all cases where either dice showed a 2 and sum of the dice was < 5. However note above that the roll (2,2) is counted twice.
So there are three unique dice roll combinations which answer the criteria of at least one die showing 2, and sum of dice < 5:
1,2
2,1
2,2
The total number of unique outcomes for two dice is 6*6=36 .
So, the probability you are looking for is 3/36 = 1/12</span>
Answer:
The answer is B and E.
Step-by-step explanation:
Answer:
it’s B
Step-by-step explanation:
just took the test
