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nata0808 [166]
3 years ago
12

What is the solution set of 12x^2-9x=0??

Mathematics
1 answer:
netineya [11]3 years ago
6 0
12x²-9x = 0
3x(4x-3)=0
4x-3=0
4x=3
x=3/4
so either x = 0  or x = 3/4
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Coach Ellis surveyed a sample of students about their favorite sport. The circle graph below shows
CaHeK987 [17]

Answer:

C. 120 students

Step-by-step explanation:

10 + 15 + 20 +30 = 75%

100 - 75 = 25%

25% chose football which is 100 students

30% chose swimming

setup proportion:

25/100 = 30/x

25x = 100(30)

25x = 3000

x  = 120

4 0
3 years ago
Si un celular Cuesta 4500 y tiene un descuento de 76%cuamto vq a pagar por el teléfono
USPshnik [31]

De acuerdo con las definiciones de precio a pagar, porcentaje de descuento y porcentaje remanente, el precio a pagar por el celular es $ 1080.

<h3>¿Cuánto cuesta un celular con descuento? </h3>

En esta situación una persona recibe un descuento por la compra de su celular, el precio a pagar es el producto de multiplicar el coste <em>sin descuento</em> y el porcentaje remanente en forma fraccionaria. El porcentaje remanente se calcula al restar el descuento del cien por ciento. A continuación, procedemos al cálculo requerido:

x = 4500 × (1 - 76/100)

x = 1080

De acuerdo con las definiciones de precio a pagar, porcentaje de descuento y porcentaje remanente, el precio a pagar por el celular es $ 1080.

Para aprender más sobre descuentos: brainly.com/question/24130820

#SPJ1

5 0
2 years ago
I need her Divideing .31 9
Aleks [24]
Answer:

If we’re dividing .31 by 9

The solution is on the photo below

Hope this helped. Have a great day!

3 0
3 years ago
What is the absolute value of 6.7
Aleonysh [2.5K]
The absolute value of 6.7 is 6.7
6 0
3 years ago
Read 2 more answers
What is the interquartile range (IQR) of the following data set 17 16 21 15 25 22 18 23 17
Pepsi [2]

IQR = 6

First locate the median Q_{2} at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles Q_{1} and Q_{3} located at the centre of the data to the left and right of the median.

Note that if any of the above are not whole values then they are the average of the values either side of the centre.

rearrange data in ascending order

15 16 ↓17 17 18 21 22 ↓23 25

                     ↑

Q_{2} = 18

Q_{1} = \frac{16+17}{2} = 16.5

Q_{3} = \frac{22+23}{2} = 22.5

IQR = Q_{3} - Q_{1} = 22.5 - 16.5 = 6




4 0
3 years ago
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