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Scilla [17]
3 years ago
15

What statistical test and how many of them will need to be used to explore the difference in average cholesterol within each gro

up before and after the treatment (i.e., how much did cholesterol level change within each group as result of the treatment)?
Mathematics
1 answer:
zepelin [54]3 years ago
6 0

Answer:

The statistical test to be used is the paired t-test.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired-samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference between these two means.

We use the paired t-test if we have two measurements on the same item, person or thing. We should also use this test if we have two items that are being measured with a unique condition.

For instance, an experimenter tests the effect of a medicine on a group of patients before and after giving the doses.

Similarly, in this case a paired t-test would be used to deter whether there was any changes in the cholesterol level within each group as result of the treatment.

Thus, the statistical test to be used is the paired t-test.

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During a weekend, the manager of a mall gave away gift cards to every 80th person who visited the mall.
yuradex [85]
What is the question??
3 0
3 years ago
F ind the volume under the paraboloid z=9(x2+y2) above the triangle on xy-plane enclosed by the lines x=0, y=2, y=x
olga nikolaevna [1]

Answer:

The answer is 48 units³

Step-by-step explanation:

If we simply draw out the region on the x-y plane enclosed between these lines we realize that,if we evaluate the integral the limits all in all cannot be constants since one side of the triangular region is slanted whose equation is given by y=x. So the one of the limit of one of the integrals in the double integral we need to evaluate must be a variable. We choose x part of the integral to have a variable limit, we could well have chosen y's limits as non constant, but it wouldn't make any difference. So the double integral we need to evaluate is given by,

V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {z} \, dx dy\\V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {9(x^{2}+y^{2})} \, dx dy

Please note that the order of integration is very important here.We cannot evaluate an integral with variable limit last, we have to evaluate it first.after performing the elementary x integral we get,

V=9\int\limits^2_0 {4y^{3}/3} \, dy

After performing the elementary y integral we obtain the desired volume as below,

V= 48 units^{3}

4 0
3 years ago
Raul is paid $75 per week plus $5 for each new gym membership he sells. He may switch to a gym that pays $50 per week and $7.50
rosijanka [135]
Answer:
11 memberships

Step-by-step:
Gym 1 = 75+5m
Gym 2 = 50+7.5m

75+5m=50+7.5m
-50 from both sides
25+5m=7.5m
-5m from both sides
25=2.5m
divide both sides by 2.5
10=m
for 10therefor 75+5m<50+7.5m he must sell 11 memberships.
5 0
3 years ago
While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between
aleksandr82 [10.1K]

Answer:

The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.

Step-by-step explanation:

Let the random variable <em>X</em> denote the water depths.

As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{b-a};\ a

Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:

P(2.25

                               =\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55

Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.

6 0
3 years ago
Which function represents the graph below?
zimovet [89]

Answer:

The inequalities all need to be of the form a < x ≤ b. i think that is it

3 0
3 years ago
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