Integer??? Idk I'm sorry....
Answer:
The two locker numbers are 68 & 69.
Step-by-step explanation:
Let one locker number be x then other will be , then other will be x+1.
We are given that sum is 137.
x+x+1=137
2x+1=137
2x=136
x = 68
The two locker numbers are 68 & 69.
Answer:
$230
Step-by-step explanation:
Answer: no solutions
7x + 5 = 7x - 3
5 = -3 [ subtract 7x from both sides ]
Since we end up with 5 = -3, a clearly false equation, we conclude that the original equation has no solutions.
i hope this helps! :D
