3 years ago

How do you sovle this 5(x – 4) + 3x – 9x = 6 – (2x + 5) + 8x

1 answer:

3 0

Answer: X=-3

Step 1) Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

5*(x-4)+3*x-9*x-(6-(2*x+5)+8*x)=0

Step 2) ((5 • (x - 4) + 3x) - 9x) - (6x + 1) = 0

Step 3) Pull out like factors : -7x - 21 = -7 • (x + 3)

Step 4) -7 • (x + 3) = 0

Step 5) Solve : -7 = 0 This equation has no solution.

A a non-zero constant never equals zero.

Step 6) Solve : x+3 = 0

Subtract 3 from both sides of the equation :

x = -3

Step-by-step explanation:

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anzhelika [568]

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Step-by-step explanation:

log (28^2) + log(525^-3) + 2x=log(10^4)
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8 0

3 years ago

Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=3, u'(0)= -4, v(0)= 2, v'(0)= -7. Find the value

3241004551 [841]

$\bf \cfrac{d}{dx}[u(x)\cdot v(x)]\implies \cfrac{du}{dx}\cdot v(x)+u(x)\cdot \cfrac{dv}{dx}\quad 
\begin{cases}
u(0)=3\qquad u'(0)=-4
\\\\
v(0)=2\qquad v'(0)=-7
\end{cases}
\\\\
\left[ \cfrac{du}{dx} \right]_{x=0}\cdot v(0)+u(0)\cdot \left[ \cfrac{dv}{dx} \right]_{x=0}$

so.. hmm pretty sure you know what that is

7 0

3 years ago

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laiz [17]

I Think The answer is c I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you

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3 years ago

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If you take a number, times by 3 then add 5. You get the same as if you took the number, times by 7 then subtract 8. What is the

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3x+5=7x-8
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