What is the area of a circle whose radius is 5 ft? 57 ft2 107 fta 207 ft? 257 ft
2 answers:
You might be interested in
Answer:
k =
Step-by-step explanation:
Fisherman noticed a stretch in the spring = 'b' centimetres
Weight of the fish = a kilograms
If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,
F = kΔx
Where k = spring constant
Δx = stretch in the spring
F = weight applied
F = mg
Here 'm' = mass of the fish
g = gravitational constant
F = a(9.8)
= 9.8a
Δx = b centimetres = 0.01b meters
Therefore, 9.8a = k(0.01b)
k =
k =
Therefore, spring constant of the spring will be determined by the expression, k =