Option A :
is the solution of the equation.
Explanation:
The equation is 
To determine the value of x, let us simplify the equation.
Subtracting 5 from both sides of the equation, we have,

Simplifying, we get,

Now , dividing both sides of the equation by 8, we get,

Using the logarithmic definition that if
then 
Thus, rewriting the above expression
using the logarithmic definition, we have,
⇒ 
Substituting the value of
, we get,

Rounding off the answer to two decimal places, we get,

Hence, the solution of the equation is 
Therefore, Option A is the correct answer.