All categories

3 years ago

It's 3 triangles right ?? I just to make sure am right. How many triangles equal a Circle

Mathematics

2 answers:

Gekata [30.6K]3 years ago

8 0

The answer is 5 Triangles = one Circle

PSYCHO15rus [73]3 years ago

3 0

It is 3 triangles your right

You might be interested in

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 point

Liono4ka [1.6K]

Idk this but it might be the points

8 0

2 years ago

Factor completly x^2 -64

Hoochie [10]

∑ Hey, jillianwagler ⊃

Answer:

$\left(x+8\right)\left(x-8\right)$

Step-by-step explanation:

⇒ Given info:

Factor completely $x^2 -64$

⇒ Solution:

Rewrite 64 as 8 ² because 8² is equal to 64. 8 ² = 8 × 8 = 64.

$=x^2-8^2$

Applying difference of two squares formula: $x^2-y^2=\left(x+y\right)\left(x-y\right)$

$=x^2-8^2=\left(x+8\right)\left(x-8\right)\\$

$=\left(x+8\right)\left(x-8\right)$

Answer~: $\left(x+8\right)\left(x-8\right)$

xcookiex12

8/19/2022

7 0

2 years ago

What is the conjugate of 1 + √5

RUDIKE [14]

Answer:

Exact Form:

1 + √5

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

8 0

2 years ago

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

3 years ago

Urgent!!!! The scores of a high school entrance exam are approximately normally distributed with a given mean Mu = 82.4 and stan

Effectus [21]

Answer:95%

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers