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2 years ago

An angle is double its complement. find the angle and the complement

2 answers:

4 0

Complement means the other angle that will sum up to 90°

So:

x + 2x = 90°
3x = 90
x = 30°

So, it is 30° and 30 * 2°, or 60°

aivan3 [116]2 years ago

4 0

Answer:

60⁰

Step-by-step explanation:

Angke = x

Complement = 90 - x

Given:

x = 2 (90 - x)

x = 180 - 2x

3x = 180

x = 60⁰

Complement = 30⁰

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What is the factored form of x2 - 12x - 45?

Olenka [21]

Answer:

(x - 15)(x + 3)

Step-by-step explanation:

Factors of 45 include 5 and 9, 3 and 15, 1 and 45, and so on.

Note that 3*15 =+45; this is not what we wanted. Thus, try (-3)*15 = -45.

Do -3 and 15 combine to yield -12? No. Thus drop (-3)(15) and try (3)(-15).

Do 3 and -15 combine to yield -12? YES

Therefore, the factored form of x² - 12x - 45 is (x - 15)(x + 3).

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2 years ago

A pea plant is heterozygous for the genes for seed form (Rr) and seed color (Gg). It is crossed with a pea plant of the genotype

mylen [45]

Answer:

Step-by-step explanation:

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2 years ago

Special triangles 2 back

AleksAgata [21]

Answer:

Step-by-step explanation:

10. From the given figure,

$\frac{18}{y}=sin60^{0}$

$y=\frac{36}{\sqrt{3}}$

11. From the given figure,

$\frac{12}{y}=sin60^{0}$

$y=\frac{12{\times}2}{\sqrt{3}}=\frac{24}{\sqrt{3}}$

and $\frac{x}{y}=cos60^{0}$

$x=\frac{24}{\sqrt{3}{\times}2}=\frac{12}{\sqrt{3}}$

12. The sides of an equilateral triangle has length=10 inches, therefore AB=BC=AC=10

Also, AD is the height of the given triangle,then BD=DC=5

From triangle ADC,

$(AC)^{2}=(AD)^{2}+(DC)^{2}$

$100=(AD)^{2}+25$

$75=(AD)^{2}$

$AD=\sqrt{75}inches$

Hence, height of the triangle is $\sqrt{75}inches$

13. Height of the ramp from the ground is 8ft.

therefore, let BC=x

$\frac{8}{BC}=tan30^{0}$

$\frac{8}{x}=\frac{1}{\sqrt{3}}$

$x=8\sqrt{3}$

14. Let BC=x and AB=y

then, $\frac{x}{18}=cos30^{0}$

$x=18{\times}\frac{\sqrt{3}}{2}=9\sqrt{3}$

and $\frac{y}{x}=tan30^{0}$

$y=9$

The perimeter of triangle is=Sum of all the sides=AB+BC+AC= $9\sqrt{3}+9+18= 9\sqrt{3}+27=9(1.73)+27=42.57 inches$

15. Let AB be the height of the tree, then

$\frac{AB}{8}=tan30^{0}$

$AB=8{\times}\frac{1}{\sqrt{3}}=\frac{8}{1.73}=4.62m$

16. According to question,

$\frac{h}{24}=sin30^{0}$

$h=\frac{24}{2}=12ft$

7 0

2 years ago

Read 2 more answers

Vehicles entering an intersection from the east are equally likely to turn left, turn right, or proceed straight ahead. If 50 ve

ira [324]

Answer:

The probability that at least two-third of vehicles in the sample turn is 0.4207.

Step-by-step explanation:

Let X = number of vehicles that turn left or right.

The proportion of the vehicles that turn is, p = 2/3.

The nest n = 50 vehicles entering this intersection from the east, is observed.

Any vehicle taking a turn is independent of others.

The random variable X follows a Binomial distribution with parameters n = 50 and p = 2/3.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

Check the conditions as follows:

$np=50\times \frac{2}{3}=33.333>10\\\\n(1-p)=50\times \frac{1}{3}= = 16.667>10$

Thus, a Normal approximation to binomial can be applied.

So, $X\sim N(np, np(1-p))$

Compute the probability that at least two-third of vehicles in the sample turn as follows:

$P(X\geq \frac{2}{3}\times 50)=P(X\geq 33.333)=P(X\geq 34)$

$=P(\frac{X-\mu}{\sigma}>\frac{34-33.333}{\sqrt{50\times \frac{2}{3}\times\frac {1}{3}}})$

$=P(Z>0.20)\\=1-P(Z$

Thus, the probability that at least two-third of vehicles in the sample turn is 0.4207.

6 0

2 years ago

Please select a b c or d

andriy [413]

I think C is the answer

3 0

2 years ago