The formula for centripetal acceleration is v^2/r, where v is the tangential velocity, and r is the radius.
<span>Alternatively, w^2r where w is the angular velocity and r is the radius.
</span><span>The centripetal acceleration is ar=(((1.70 rev/s)*(2*pi rad/rev))^2)*(0.132m)= 15.06 m/s^2 </span>
<h3><u>Answer;</u></h3>
= 2868 Newtons
<h3><u>Explanation;</u></h3>
Centripetal force is a force that acts on an object or a body in circular path and is directed towards the center of the circular path.
Centripetal force is given by the formula;
mv²/r ; where m is the mass of the body, r is the radius of the circular path and v is the velocity of a body;
mass = 65 kg, velocity = 15 m/s and r = 5.1 m
Therefore;
Centripetal force = (65 × 15²)/ 5.10
= 2867.65 Newtons
= 2868 N
Answer:
-90.8 Joules
Explanation:
A = Area of container = 50 cm²
d = Length pushed = 15 cm
P = External Pressure = 121 kPa
Change in volume
Work done
Work done by the system is -90.8 Joules
Givens:
Acceleration (a) = 32.17 ft/s² as that is the only force acting on the stone in free fall assuming no air resistance
Initial velocity (V1) = 0 ft/s as that it the starting speed of the stone as all objects about to move from rest must start at 0 velocity at rest = 0 velocity
Final velocity (V2) = 120 ft/s
Displacement aka. the
height of the cliff (Δd) = ? ft
The kinematic formula we can use is: V2² = V1² + 2(a)(Δd)
Isolate to solve for Δd and just plug in the numbers!
V2² = V1² + 2(a)(Δd)
(120)² = (0)² + 2(32.17)(Δd)
14400 = 2(32.17)(Δd)
= Δd
223.9 = Δd
Therefore, the height of the cliff is 223.9 ft! Hope this helped! :)
I need points sorry so idek the answer so u will have to ask someone else