Answer:
Explanation:
As we know that the slope of the inclination is 3%
so we can say that
since it is very small so here we can take approximation as
so we need to find the metabolic power which is given as
so here we have
now we have
Three ice skaters, numbered 1, 2, and 3, stand in a line, each with her hands on the shoulders of the skater in front. Skater 3,
1 answer:
Answer:
Following are the responses to the given question:
Explanation:
The mass (mg) is downwards, the typical pressure is upward. This pushing force of
is pushed forward by skater 3 on skater 2. (considered as rightward direction). The strength of the slater 2 in reply is the slater
Skater three moves to the left.
Its push force imparted to the skateboarder 2 in relation those above forces The force
on skater 2 by skater 1 is as a response, to a left. Skater 2's free body system is as follows:
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Hi there!
To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.
Recall:
The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.
We can plug in the known values to solve for one part of the normal force:
N = (1)(9.8)(cos30) + F(.5) = 8.49 + .5F
Now, we can plug this into the equation for the dynamic friction force:
Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F
For a block to move with constant speed, the summation of forces must be equivalent to 0 N.
If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:
Fcosθ = 1.697 + .1F
Solve for F:
Fcos(30) - .1F = 1.697
F(cos(30) - .1) = 1.697
F = 2.216 N