Answer:
a) f=0.1 Hz ; b) T=10s
c)λ= 36m
d)v=3.6m/s
e)amplitude, cannot be determined
Explanation:
Complete question is:
Determine, if possible, the wave's (a) frequency, (b) period, (c) wavelength, (d) speed, and (e) amplitude.
Given:
number of wave crests 'n'= 5
pass in a time't' 54.0s
distance between two successive crests 'd'= 36m
a) Frequency of the waves 'f' can be determined by dividing number of wave crests with time, so we have
f=n/t
f= 5/ 54 => 0.1Hz
b)The time period of wave 'T' is the reciprocal of the frequency
therefore,
T=1/f
T=1/0.1
T=10 sec.
c)wavelength'λ' is the distance between two successive crests i.e 36m
Therefore, λ= 36m
d) speed of the wave 'v' can be determined by the product of frequency and wavelength
v= fλ => 0.1 x 36
v=3.6m/s
e) For amplitude, no data is given in this question. So, it cannot be determined.
Answer:
0.497
0.38806
Explanation:
According to the question normalizing data is done by
The normalized value at 3.8 cm is 0.497
We have the relation
Hence, the theoretically expected normalized value at 6.1 cm is 0.38806
Answer:
time constant of the damping 130 seconds
Explanation:
given data
amplitude A1 = 1.6 m
time t = 1.5 min = 90 sec
amplitude A2 = 0.80 m
to find out
time constant of the damping
solution
we know here that maximum amplitude at time t is express as
A2 = A1 × e .............a
here b is time constant
so b will be from equation 1
b = ............b
put here all value top find b
b =
b =
b = 129.84
so time constant of the damping 130 seconds