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Marianna [84]
3 years ago
12

A certain 100W light bulb has an efficiency of 95%. How much thermal energy will this light bulb add to the inside of a room in

2.5h if the bulb is on for the whole time?
Physics
1 answer:
Usimov [2.4K]3 years ago
7 0
Since the bulb consumes 100 watts of power and its efficiency is 95%,
it generates 95 watts of light energy and 5 watts of heat energy whenever
it's turned on.

5 watts means  5 joules of energy per second.

(2.5 hours) x (3,600 seconds/hour) =  9,000 seconds

(9,000 seconds) x (5 joules/second)  =  45,000 joules of heat in 2.5 hours

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If a person is 6.25 m away from a 60.0 w speaker, what is the sound level they are hearing?
vodka [1.7K]

Answer:

110.87 dB

Explanation:

(I got it right on Acellus)

I= P/4(pi)r^2 = 60/4(pi)6.25^2

60/4(pi)6.25^2=0.12223

B=10log(I/Io)

B=10log(0.12223/1*10^-12) = 110.87 dB

111 in sigfigs

4 0
2 years ago
Read 2 more answers
What is the reason eclipses do not happen every full moon and new moon
ioda
The answer is D, hope this helped!
6 0
2 years ago
A particle with a charge of 5 × 10–6 C and a mass of 20 g moves uniformly with a speed of 7 m/s in a circular orbit around a sta
creativ13 [48]

Answer:

r = 0.22m

Explanation:

To find the radius of the circular trajectory, you first take into account that the centripetal force of the charged particle, is equal to the electric force between the particle that is moving and the particle at the center of the orbit.

Then, you have:

F_c=F_e=ma_c      (1)

m: mass of the particle = 20g = 20*10-3 kg

ac: centripetal acceleration = ?

q: charge of the particle = 5*10^-6C

Fe: electric force between the charges

The electric force is given by:

F_e=k\frac{qq'}{r^2}             (2)

r: radius of the orbit

q': charge of the particle at the center of the orbit = -5*10^-6C

Furthermore, the centripetal acceleration is:

a_c=\frac{v^2}{r}                 (3)

v: speed of the particle = 7m/s

You replace the expressions (2) and (3) in the equation (1) and solve for r:

k\frac{qq'}{r^2}=m\frac{v^2}{r}\\\\r=\frac{kqq'}{mv^2}

Finally, you replace the values of all parameters in the previous expression:

r=\frac{(8.98*10^9Nm^2/C^2)(5*10^{-6}C)(5*10^{-6}C)}{(20*10^{-3}kg)(7m/s)^2}\\\\r=0.22m

The radius of the circular trajectory is 0.22m

5 0
3 years ago
What are the relative positions of the sun moon and earth during a full moon?
4vir4ik [10]
They are relatively straight or as straight as they are going to get during a given month that is when a full moon occurs.
6 0
3 years ago
champion athlete can produce one horsepower (746 W) for a short period of time. The number of 16-cm-high steps a 70-kg athlete c
kicyunya [14]

Answer:

408 steps

Explanation:

Given :

Power =P= 746\  W\\mass=M\ =\ 70\  kg\\time\  =\ T\ =\ 1\  minute\\Height=H=16\ cm=0.16\  m

Consider that n is the number of steps .

We know that

Power=P =  \frac{work done}{time\  taken} \\

that can be written as

P=\frac{n*MgH}{T}

In terms of n ,

n=\frac{P*T}{MgH} \\Putting\  the\  value\  of\  P\ ,T\  M\  ,H\  and\  G=9.8\ ms^{2} \ in\  the\  previous \ equation\  we\  getn=\frac{ 746 W*60s}{ 70 kg *9.8 m/s2*0.16m} \\n=407.8\ steps

~n=408 steps

7 0
3 years ago
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