All categories

3 years ago

If an LRC circuit creates an E&M wave of 1,591 KHz, what is the wave length of the wave?

Physics

1 answer:

lana [24]3 years ago

7 0

Answer:

Wavelength of the wave is 188.56 meters.

Explanation:

Given that,

Frequency of the LCR circuit, $f=1591\ KHz=1591\times 10^3\ Hz$

We need to find the wavelength of this EM wave. It is given by :

$\lambda=\dfrac{c}{f}$

c is the speed of light

$\lambda=\dfrac{3\times 10^8\ m/s}{1591\times 10^3\ Hz}$

$\lambda=188.56\ m$

So, the wavelength of the wave is 188.56 meters. Hence, this is the required solution.

You might be interested in

Please help me i dont understand it <br><br><br><br> This subject is Earth science

Anton [14]

Here are your answers

6 0

3 years ago

Jesse has 200 peanut butter cups and she gives some of them to her friend. How many peanut butter cups did she give her friend?

pychu [463]

Answer:

99 peanut butter

Explanation:

you minus 200 - 101 you get 99 peanut butter

3 0

3 years ago

Which of these substances would rise to the top if placed in a container with the rest?

Vladimir [108]

What substances? Depends on their density, the lower density floats on top. For example, oil floats on top of water

4 0

4 years ago

Someone pls answer this

andriy [413]

Answer:

<em>The speed of metal block B is 5 m/s after the collision</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=mv.

If we have a system of bodies, then the total momentum is the sum of them all

$P=m_1v_1+m_2v_2+...+m_nv_n$

If some collision occurs, the velocities change to v' and the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

In a system of two masses, we have:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

The metal block A has a mass of m1=3.2 Kg and moves at v1=4 m/s. Metal block b has a mass of m2=1.6 Kg and is initially at rest v2=0.

After the collision occurs, block A moves at v1'=1.5 m/s. We need to calculate the speed of the metal block B. Solving for v2':

$\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}$

Substituting the given values:

$\displaystyle v'_2=\frac{3.2*4+1.6*0-3.2*1.5}{1.6}$

$\displaystyle v'_2=\frac{8}{1.6}$

$\displaystyle v'_2=5\ m/s$

The speed of metal block B is 5 m/s after the collision

8 0

3 years ago

What is the magnetic force value due to 3.5nanocoloumb charge moves to the

sertanlavr [38]

The force on the charge is 1.1×10⁻⁸ N.

<h3>What is force?</h3>

Force can be defined as the product of the mass of a body and its acceleration

To calculate the force on the charge, we use the formula below.

Formula:

F = qvBsin∅............. Equation 1

Where:

q = charge
v = velocity
B = magnetic field
∅ = Angle.

From the question,

Given:

B = 25 mT = 0.025 T
v = 250 m/s
q = 3.5 nC = 3.5×10⁻⁹ C
∅ = 30°

Substitute the given values into equation 1

F = (0.025)(250)(3.5×10⁻⁹)(sin30°)

F = 1.093×10⁻⁸ N
F ≈ 1.1×10⁻⁸ N

Hence, the force on the charge is 1.1×10⁻⁸ N.

Learn more about force here: brainly.com/question/12970081

6 0

3 years ago