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trapecia [35]
3 years ago
7

How much work is done when a car is moved 10 m with a force of 3.4 N?

Physics
2 answers:
Arisa [49]3 years ago
7 0

Answer:

34J I assume

Explanation:

force×distance is work done. 10×3.4 is 34. therefore its 34 joules of work done

Licemer1 [7]3 years ago
6 0

Answer:

34J

Explanation:

The formula for work is W=Force x Distance

W=FxD

F=3.4N

D=10m

W=10x3.4

W=34 Joules

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In the photoelectric effect, the greater the frequency of the illuminating light, the greater the:_______
TEA [102]

Answer:

B. Maximum velocity of ejected electrons.

Explanation:

The ejection of electrons form a metal surface when the metal surface is exposed to a monochromatic electromagnetic wave of sufficiently short wavelength or higher frequency (or equivalently, above a threshold frequency),  which leads to the enough energy of the wave to incident and get absorbed to the exposed surface emits electrons. This phenomenon is known as the photoelectric effect or photo-emission.

The minimum amount of energy required by a metal surface to eject an electron from its surface is called work function of metal surface.

The electrons thus emitted are called photo-electrons.

The current produced as a result is called photo electricity.

Energy of photon is given by:

E=h.\nu

where:

h = Planck's constant

\nu= frequency of the incident radiation.

8 0
3 years ago
Astronauts on a distant planet set up a simple pendulum of length 1.2 m. The pendulum executes simple harmonic motion and makes
Iteru [2.4K]

Answer:

If you use P = 2 * pi * (L / g)^1/2  for the period of the simple pendulum

g = 4 * pi^2 * 1.2 / 2.8^2 = 6.04 m/s2

Note: omega = 2 pi * f = 2 pi / P  and omega = (g / L)^1/2

7 0
3 years ago
What kind of variation is there in the mechanical energy as the cart rolls down the ramp? Does this agree with your prediction?
Harlamova29_29 [7]

Answer:

 Em₀ = U = m g h ,  Em_{f} = K = ½ m v²

Explanation:

When a car is on a ramp it has a certain amount of mechanical energy. At the highest point of the ramp the mechanical energy is fully potential given by

          Em₀ = U = m g h

As part of this energy descends down the ramp, part of this energy is transformed into kinetic energy and has one part of each, even though the sum remains the initial energy

            Em = K + U = ½ m v² + mg y

        y <h

when it reaches the bottom of the ramp it has no height therefore there is no potential energy, all of it has been transformed into kinetic energy

          Em_{f} = K = ½ m v²

This energy transformation is in the case that the friction force is zero.

If there is a friction force, it performs work against the low car, it is reflected in an increase in the internal energy (temperature) of the car. In this case the energy in the lower part is less than the initial one by a factor

         W_{nc} = - fr L

therefore the numeraire values ​​of the velocity are lower, due to the energy lost by friction.

6 0
3 years ago
A thin, rectangular sheet of metal has mass M and sides of length a and b. Find the moment of inertia of this sheet about an axi
slega [8]
We divide the thin rectangular sheet in small parts of height b and length dr. All these sheets are parallel to b. The infinitesimal moment of inertia of one of these small parts is
dI =r^2*dm
where dm =M(b*dr)/(ab)
Now we find the moment of inertia by integrating from -a/2 to a/2
The moment of inertia is
I= \int\limits^{-a/2}_{a/2} {r^2*dm} = M \int\limits^{-a/2}_{a/2} r^2(b*dr)/(ab)=(M/a)(r^3/3) (from (-a/2) toI=(M/3a)(a^3/8 +a^3/8)=(Ma^2)/12 (a/2))



4 0
4 years ago
What effect does observing a substance's physical properties have on the substance
Phoenix [80]
It can be observed without changing the identity of the object.
4 0
3 years ago
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