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Neporo4naja [7]

4 years ago

14

Which of the two resistors dissipates the larger amount of power?

1 answer:

Aloiza [94]4 years ago

3 0

The circuit shown has a battery and two resistors, with R1>R2. Which of the two resistors dissipates the larger amount of power? Explain

Rank in order, from largest to smallest, the three currents I1 TO I3. And explain why?

The two batteries are identical and the four resistors all ahve exactly the same resistance.

a) Compare change in V(ab), V(cd), and V(ef). Are they all the same? In not, rank them in decreasing order. Explain you reasoning

b) Rank in order, from largest to smallest, the five currents I1 to I5, and ezplain why

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Momentum depends on what two factors

IrinaVladis [17]

mass and velocity

Explanation:

Momentum depends on two important factors which are the mass and velocity of a body.

Momentum = mass x velocity

Momentum can be defined as the product of mass and velocity.
It is a vector quantity that has both magnitude and directions.
Momentum is a very important quantity in physics as it shows the impact of a force on another.
The unit is Kgm/s²
It is the same as impulse.

learn more:

Momentum brainly.com/question/2990238

#learnwithBrainly

3 0

3 years ago

How does temperature change as you go from the surface toward the center of the earth?

Nastasia [14]

Because lava is in the center and lavas hot

8 0

3 years ago

A rocket with a mass of 62,000 kg (including fuel) is burning fuel at the rate of 150 kg/s and the speed of the exhaust gases is

mezya [45]

Answer:

h≅ 58 m

Explanation:

GIVEN:

mass of rocket M= 62,000 kg

fuel consumption rate = 150 kg/s

velocity of exhaust gases v= 6000 m/s

Now thrust = rate of fuel consumption×velocity of exhaust gases

=6000 × 150 = 900000 N

now to need calculate time t = amount of fuel consumed÷ rate

= 744/150= 4.96 sec

applying newton's law

M×a= thrust - Mg

62000 a=900000- 62000×9.8

acceleration a= 4.71 m/s^2

its height after 744 kg of its total fuel load has been consumed

$h= \frac{1}{2}at^2$

$h= \frac{1}{2}4.71\times4.96^2$

h= 58.012 m

h≅ 58 m

4 0

3 years ago

Something is thrown in the air and 5.35 seconds later it lands on something 2.1 meters from the ground. How fast was it thrown u

UNO [17]

Answer:

26.6 m/s

Explanation:

Given:

Δy = 2.1 m

t = 5.35 s

a = -9.8 m/s²

Find: v₀

Δy = v₀ t + ½ at²

(2.1 m) = v₀ (5.35 s) + ½ (-9.8 m/s²) (5.35 s)²

v₀ = 26.6 m/s

5 0

3 years ago

Water is flowing through a channel that is 12m wide with a

Alexus [3.1K]

Answer:

Velocity from second channel will be 1.6875 m/sec

Explanation:

We have given width of the channel , that is diameter of the channel 1 $d_1$ = 12 m

So radius $r_1=\frac{d_1}{2}=\frac{12}{2}=6m$

Speed through the channel 1 $v_1=0.75m/sec$

Width , that is diameter of the channel 2 $d_2=4m$

So $r_2=2m$

From continuity equation

$A_1v_1=A_2v_2$

$\pi \times 12^2\times 0.75=4\times \pi\times 4^2\times v_2$

$v_2=1.6875m/sec$

So velocity from smaller channel will be 1.6875 m /sec

6 0

3 years ago