<h3>Answers:</h3>
- (a) It is <u>never</u> one-to-one
- (b) It is <u>never</u> onto
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Explanation:
The graph of any constant function is a horizontal flat line. The output is the same regardless of whatever input you select. Recall that a one-to-one function must pass the horizontal line test. Horizontal lines themselves fail this test. So this is sufficient to show we don't have a one-to-one function here.
Put another way: Let f(x) be a constant function. Let's say its output is 5. So f(x) = 5 no matter what you pick for x. We can then show that f(a) = f(b) = 5 where a,b are different values. This criteria is enough to show that f(x) is not one-to-one. A one-to-one function must have f(a) = f(b) lead directly to a = b. We cannot have a,b as different values.
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The term "onto" in math, specifically when it concerns functions, refers to the idea of the entire range being accessible. If the range is the set of all real numbers, then we consider the function be onto. There's a bit more nuance, but this is the general idea.
With constant functions, we can only reach one output value (in that example above, it was the output 5). We fall very short of the goal of reaching all real numbers in the range. Therefore, this constant function and any constant function can never be onto.
A.1
B.3
C.3
Just did this assignment.
Answer:
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
Since AB and BC are perpendicular, then
∠ABC = 90° and
∠ABD + ∠DBC = ∠ABC ← substitute values
3r + 5 + 5r - 27 = 90, that is
8r - 22 = 90 ( add 22 to both sides )
8r = 112 ( divide both sides by 8 )
r = 14
Hence
∠ABD = 3r + 5 = (3 × 14) + 5 = 42 + 5 = 47°
∠DBC = 5r - 27 = (5 × 14) - 27 = 70 - 27 = 43°
Since slope is y=mx+b and m is -3 you would plug in the (5,1) which 5 is x and 1 is y. you would plug them into the y=mx+b and then u would get 1= -3(5) +b and then it would go into 1= -15 +b then -15 would move to the other side and b=16
Hoped this helped! :)
