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Lorico [155]
3 years ago
11

(fx+cd)/(x-f)=1/2 solve for x

Mathematics
1 answer:
sesenic [268]3 years ago
6 0

Answer:

Step-by-step explanation:

(fx+cd)/(x-f)=1/2

Cross multiplication,

2*(fx + cd) = 1 * (x-f)

2fx + 2cd = x - f

2fx - x  = -2cd - f

x (2f - 1) = -2cd -f

x = (-2cd-f )/ (2f-1)

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Solve:
Delvig [45]

Answer:

D. x=12/11 or x=32/11.

4 0
3 years ago
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Choose the midpoint of the line segment with endpoints at (5, 9) and (11, 15).
Tcecarenko [31]

Answer:

C) (8,12)

Step-by-step explanation:

MP= (\frac{x_1+x_2}{2} )(\frac{y_1+y_2}{2} )\\MP= (\frac{5+11}{2} )(\frac{9+15}{2} )\\MP= (\frac{16}{2} )(\frac{24}{2} )\\MP= (8,12)

8 0
3 years ago
A number subtracted from 11 is the quotient of -20 and -2. Find the number.
Troyanec [42]

Answer:

1

Step-by-step explanation:

-20 divided by -2 is the same as 20 divided by 2, which is 10. 11-10=1 so the answer is 1.

8 0
3 years ago
La casa de prestamos la mejor cobra el 7% de interes mensual.Es decir por cda 100 paga solo 7 pesos
Marizza181 [45]

Responder:

Por favor, consulte la explicación.

Explicación paso a paso:

Dado que :

Los mejores cargos por préstamos hipotecarios:

Interés mensual = 7%

Intereses pagados sobre capital de 100 pesos

Intereses pagados = principal * tasa de interés

Intereses pagados = 100 * 7%

Intereses pagados = 100 * 0.07

Intereses pagados = 7 pesos

De ahí que los intereses pagados por un préstamo de 100 pesos sean 7 pesos

3 0
2 years ago
A 15 ft. telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42° angle
Lorico [155]

Answer:

Correct choice is A

Step-by-step explanation:

Consider right triangle ABC formed by the telephone pole (side AB) and ground (side BC). In this triangle AC is the length of the wire, BC is the distance from the base of the pole to the spot where the wire touches the ground and AB=15 ft, ∠ACB=42°.

Then

  • \sin 42^{\circ}=\dfrac{AB}{AC}\Rightarrow AC=\dfrac{AB}{\sin 42^{\circ}}=\dfrac{15}{\sin 42^{\circ}}\approx 22.4\ ft.
  • \tan 42^{\circ}=\dfrac{AB}{BC}\Rightarrow BC=\dfrac{AB}{\tan 42^{\circ}}=\dfrac{15}{\sin 42^{\circ}}\approx 16.7\ ft.

8 0
3 years ago
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