Answer:
discriminant=0
Number of real solutions=1
Step-by-step explanation:
Given the equation:
-9x^2-6x-1=0
Let a: coefficient of x^2
Let b: coefficient of x
Let c: constant
a=-9
b=-6
c=-1
The formula of the discriminant is given by:
discriminant= b^2 - 4ac
discriminant= (-6)^2 - 4(-9)(-1)
= 36 - 36 = 0
We know that:
If discriminant<0 then the equation has no real root
If discriminant=0 the equation has one real root
If discriminant>0 the equation has 2 real roots
Here we got discriminant=0 so the quadratic equation has 1 real root.
Answer: c
Step-by-step explanation:
Hey there!
"15 more than" will mean that 15 will be added to another term. The other term is "half a number", meaning 0.5x, where x is the number. This equation is equal to 9. The final equation is 0.5x + 15 = 9.
To solve this, cancel out the terms until you find what x is equal to:
0.5x + 15 = 9 (subtract 15 from both sides)
0.5x = –6 (divide both sides by 0.5)
x = –12 (final answer)
Hope this helped you out! :-)
Answer:
4.1, 4.14, 4 1/5, 17/4, 4.41
Step-by-step explanation:
