The amount invested in the account that earns 10% interest is $2000.
The amount invested in the account that earns 13% interest is $3000.
<h3>What are the linear equations that represent the question?</h3>
a + b = 5000 equation 1
0.1a + 0.13b = 590 equation 2
Where:
- a = amount invested in the account that earns 10% interest
- b = amount invested in the account that earns 13% interest
<h3>How much was invested in the account that earns 13% interest ?</h3>
Multiply equation 1 by 0.1
0.1a + 0.1b = 500 equation 3
Subtract equation 3 from equation 1
90 = 0.03b
Divide both sides by 0,03
b = $3000
<h3>How much was invested in the account that earns 10% interest ?</h3>
Subtract $3000 from $5000: 5000 - 3000 = $2000
To learn more about simultaneous equations, please check: brainly.com/question/25875552
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Let A be the number of Adult tickets and S, the Students'
A+ S = 273, but we know that S=2.A
Then A + 2A = 273 ; 3A =273; A =273/3 =91
So 91 tickets were sod to Adults & 182 Tickets to Students
Step-by-step explanation:
Answer:
2ac = 2(1/2)(9) = 9
Step-by-step explanation:
Step 1: Plug in your variables.
a = 1/2 c = 9
2ac becomes 2 (1/2)(9)
Step 2 (Follow this ONLY if they ask you to SOLVE):
2 (1/2)(9) = 2 x 1/2 × 9
2 × 1/2 = 1
1 x 9 = 9
Therefore, 2ac = 9
