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iogann1982 [59]
3 years ago
7

It take Rick 5 minutes to wash 4 dishes. If he continue to work at this rate.how many minutes will it take Rick to wash 24 dishe

s?
Mathematics
1 answer:
juin [17]3 years ago
4 0

5 minutes         x minutes

---------------  =   -------------

4 dishes           24 dishes


using cross products

5 * 24 = 4 * x

divide each side by 4

5*24/4 = x

30=x

It will take 30 minutes

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how many ways can Aileen choose 2 pizza toppings from a menu of 19 toppings if each topping can only be chosen one​
alexdok [17]

Answer:

There are 342 different combinations.

Step-by-step explanation:

Ok, Aileen is choosing toppings for a pizza.

She can choose two.

There are 19 options that can be chosen once.

The first thing we need to do, is find all the "selections".

Here we have two selections:

Topping number 1

Topping number 2.

Now we need to find the number of options for each one of these selections:

Topping number 1:  Here we have 19 options.

Topping number 2:  Here we have 18 options (because one was already taken in the previous selection)

The total number of combinations is equal to the product between the numbers of options.

C = 19*18 = 342

There are 342 different combinations.

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3 years ago
I need help with the problem
Kobotan [32]
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3 years ago
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How many 2 letter permutations can be made from the word "letter"
Leto [7]

Answer:

Brainliest for Brainliest

Step-by-step explanation:

5 0
3 years ago
Use the following scenario to answer the question below:
Aleks [24]

Answer:

9 hr * 60 min/hr = 540 min. 540 min * 60 sec/min = 32,400 sec. Use the method described by panic mode: round the number down until there is only one non-zero digit left. Here, 32,400 rounds down to 30,000. Now count the number of zeroes; the result is the order of magnitude: 4. (You see this in scientific notation also: 30,000 = 3 × 10^4.)

5 0
2 years ago
Solve the given initial-value problem. x^2y'' + xy' + y = 0, y(1) = 1, y'(1) = 8
Kitty [74]
Substitute z=\ln x, so that

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dz}\cdot\dfrac{\mathrm dz}{\mathrm dx}=\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dz}+\dfrac1x\left(\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dz^2}\right)=\dfrac1{x^2}\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)

Then the ODE becomes


x^2\dfrac{\mathrm d^2y}{\mathrm dx^2}+x\dfrac{\mathrm dy}{\mathrm dx}+y=0\implies\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)+\dfrac{\mathrm dy}{\mathrm dz}+y=0
\implies\dfrac{\mathrm d^2y}{\mathrm dz^2}+y=0

which has the characteristic equation r^2+1=0 with roots at r=\pm i. This means the characteristic solution for y(z) is

y_C(z)=C_1\cos z+C_2\sin z

and in terms of y(x), this is

y_C(x)=C_1\cos(\ln x)+C_2\sin(\ln x)

From the given initial conditions, we find

y(1)=1\implies 1=C_1\cos0+C_2\sin0\implies C_1=1
y'(1)=8\implies 8=-C_1\dfrac{\sin0}1+C_2\dfrac{\cos0}1\implies C_2=8

so the particular solution to the IVP is

y(x)=\cos(\ln x)+8\sin(\ln x)
4 0
3 years ago
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