Since LM = AM, point M must be on the perpendicular bisector of AL. Since AM = BM, BL must be perpendicular to AL. This makes ∆ALC a right triangle with hypotenuse AC twice the length of side AL. Hence ∠LAC = ∠LAB = 60°, and AL is angle bisector, median, and altitude.
ΔABC is isosceles with ∠A = 120°, and ∠B = ∠C = 30°.
Answer:
5 units
Step-by-step explanation:
Image of the trapezoid is attached.
To find the height of the trapezoid (image attached), let's take the formula for area of a trapezoid.
The formula for area of a trapezoid is:
Here, a and b represents the bases of the trapezoid.
a = 6
b = 10
h which represents height is unknown.
A = 40
Substitute figures:
Solve for h:
The height of the trapezoid is 5 units
