Given set S = <span>{A, B, C, D, E, F, G, H}
There are 8 elements in set S and we are to choose 3 letters at random, the number of ways to choose such is x. It is simply similar to choosing 5 letters at random, which is also equal to x. Since order doesn't matter, n! / (n-m)! where n = 8 and m = 3, which is 336 ways. </span>
Answer:
49×66+49×34 = 49× (66+34)
Answer:
Well in set A, all of the sides are the same length but they are different shapes.
In set B, all of the angles are the same, they are just differnet shapes.
Hope this helps! :)
