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Mamont248 [21]
3 years ago
5

Olga used 100 ounces of flour to make 225 muffins. How many ounces of flour will be used to make 300 muffins?

Mathematics
2 answers:
Kamila [148]3 years ago
7 0
The question asks for the amount of flour he would use to make 300 muffins given that he uses the same amount of flour to make his muffins.

The first time he uses 100 ounce of flour to make 225 muffins

We want to find how much flour he uses for each muffin in order to find how much flour he needs to make 300 muffins.

100ounces/225muffins=4/9 ounce per muffin

4/9 ounce per muffin x 300 muffins=400/3 ounces of flour
Levart [38]3 years ago
3 0
125 ounces of flower
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Equation:
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2 years ago
How do i solve thisx/12= 0​
Elis [28]

Answer:

0

Step-by-step explanation:

0÷12=0

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7 0
3 years ago
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Find the length of the third side. If necessary, round to the nearest tenth.<br> 6<br> 14
Romashka-Z-Leto [24]

Answer:

≈ 12.6

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

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let x be the third side, then

x² + 6² = 14²

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8 0
2 years ago
Select the correct answer.
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Step-by-step explanation:

8 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
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