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malfutka [58]
3 years ago
7

What is 13 4/5 - 10 3/11​

Mathematics
2 answers:
Irina18 [472]3 years ago
7 0

Answer:

3 29/55

Step-by-step explanation:

aniked [119]3 years ago
6 0

Answer:

3 29/55

Step-by-step explanation:

In the attached file

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Pls help me with this !!!!! it is urgent
OLEGan [10]
The answer is 1A definitely
4 0
3 years ago
Solve the exponential equation: 4x - 2 = 2x​
svetlana [45]

Answer:

x= 1

Step-by-step explanation:

Solve

Let's solve your equation step-by-step.

4x−2=2x

Step 1: Subtract 2x from both sides.

4x−2−2x=2x−2x

2x−2=0

Step 2: Add 2 to both sides.

2x−2+2=0+2

2x=2

Step 3: Divide both sides by 2.

2x

2

=

2

2

x=1

8 0
2 years ago
What is the shape name<br>please do fast.​
vivado [14]

Answer:

\boxed{\sf Parallelogram}

Step-by-step explanation:

A parallelogram has opposite parallel sides and it is a quadrilateral.

7 0
3 years ago
Read 2 more answers
What is the value of x?
grandymaker [24]

i got 5.14cm i don´t know how much you are supposed to round though

36/42= 0.857142857 x 6=5.142857143

6 0
3 years ago
1) The deer population in a national park is expected to decline over time. The park
Lorico [155]

Answer:

Here's what I find.

Step-by-step explanation:

You have 800 deer at the end of Year 1, and you expect the population to decrease each year thereafter.

a) i) The recursive formula

Let dₙ = the deer population n years after the initial measurement.

d_{n} = d_{n - 1}r^{n}

For this situation,

d_{n} = d_{n - 1}(0.5)^{n}

a) ii) Definitions

n = the number of years from first measurement

r = the common ratio, that is, the deer population at the end of one year divided by the population of the previous year.

a) iii) First term of sequence

The first term of the sequence is d₀, the population when first measured.

b) The function formula

The formula for the nth term of a geometric series is

d_{n} =d_{0}r^{n - 1}

c) Value of d₀

Let n = 2; then d₂ = 800

\begin{array}{rcl}800 & = & d_{0}(0.5)^{2 - 1}\\800 & = & d_{0}(0.5)\\\\d_{0} & = & \dfrac{800}{0.5}\\\\& =&\mathbf{1600}\\\end{array}

4 0
3 years ago
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