How many liters give u 3.1KL

Mathematics

1 answer:

MariettaO [177]3 years ago

7 0

Answer:

3100 liters

Step-by-step explanation:

multiply the value by 1000

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Third degree, with zeros of -3,-2, and 1, and passes through the point (2,11) P(x)=

Soloha48 [4]

Answer:

$P(x)=0.55(x+3)(x+2)(x-1)$

Step-by-step explanation:

If a polynomial function is third degree function and has zeros at -3,-2, and 1, then its equation is

$P(x)=a(x-(-3))(x-(-2))(x-1)\\ \\P(x)=a(x+3)(x+2)(x-1)$

It passes through the point (2,11), so the coordinates of the point satisfy the equation of the function:

$11=a(2+3)(2+2)(2-1)\\ \\11=a\cdot 5\cdot 4\cdot 1\\ \\20a=11\\ \\a=\dfrac{11}{20}=0.55\\ \\P(x)=0.55(x+3)(x+2)(x-1)$

6 0

3 years ago

The half-life of rhodium, Rh-106, is about 30 seconds. You start with 500 grams.

kondaur [170]

I think the logical question for this would be to find the reaction rate constant, k, for radioactive decay of Rhodium. The general formula is:

ln A/A₀ = -kt,
where
A is the amount of substance after time t,
A₀ is the original amount of substance
t is the time

After 30 s, the amount of Rhodium would be in half. So, A/A₀ = 1/2

ln(1/2) = -k(30 s)
k = 0.023 s⁻¹

7 0

3 years ago

10 points. . .. this is for my brother they have changed stuff so much from when i was in 6th

Mrac [35]

Answer: 1.885 miles

Step-by-step explanation:

Given: One lap around a park = 0.58 mile

The number of laps walked by Jessica= 3.25

Then, in miles , the distance walked around the park by Jessica will be (Multiply the number of laps to the value of one lap in miles) :

Hence, Jessica walked 1.885 miles around the park.

5 0

3 years ago

Read 2 more answers

What is the least common multiple of the two denominators 6/8 , 4/32

RoseWind [281]

4 is the common multiple of 2 denominators

7 0

3 years ago

HELP!!!!

zimovet [89]

Answer:

$37.55\ m$

Step-by-step explanation:

we know that

The perimeter of the figure is equal to the perimeter of semicircle plus the perimeter of quarter circle plus two times the length of $2\ m$ plus two times the length of $5\ m$