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stealth61 [152]
3 years ago
14

Solve the equation 3/2(2-6x)+1=3-5x

Mathematics
1 answer:
tigry1 [53]3 years ago
8 0

Answer:

Here's a tip:

Step-by-step explanation:

Use the acronym PEMDAS to solve.

P arenthesis

E xpoments

M ultiplication

D ivsion

A ddition (Left to right)

S ubtraction (Left to right)

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The answer would be 2790
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In Exercises 5-7, find all the exact t-values for which the given statement is true,
bearhunter [10]

Answer:  See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians:     t = 0π + 2πn

In degrees:   t = 0° + 360n

******************************************************************************

6)\quad sin (t) = \dfrac{1}{2}

Where on the Unit Circle does   sin = \dfrac{1}{2}

<em>Hint: sin is only positive in Quadrants I and II</em>

\text{Answer: at}\  \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n

In degrees:    t = 30° + 360n  and  150° + 360n

******************************************************************************

7)\quad tan (t) = -\sqrt3

Where on the Unit Circle does    \dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

\text{Answer: at}\  \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n

In degrees:    t = 120° + 360n  and  300° + 360n

4 0
3 years ago
There are two cell phone plans available from Cells Phones R Us company. Plan A charges $35 a month plus $0.05 for every text me
Yuri [45]

if PLAN A is cheaper than PLAN B then,

P (A) < P (B)

30+0.01t < 20+0.05t      (subtract 0.05t from both sides)

29.95-0.04t < 19.95        (subtract 29.95 from both sides)

-0.04t < -10                      (divide both sides by -0.04)

t > 250

So plan A is cheaper than plan B when you send more than 250 texts.

Hope it helps.

5 0
3 years ago
If a chord of a circle is 6 and is twice as far from the center chord of length 12, how long is the radius of the circle?
Ad libitum [116K]

Answer and explanation:

A center chord in a circle is the diameter of that circle. Therefore a center chord of a circle is different from other chords that touch two points on the circle but not in the center of the circle. A diameter of a circle is the chord that runs the length of the center of the circle touching two points at the edge of the circle. A diameter is twice the radius of the circle. So if the diameter of the circle is 12cm then the radius of the circle is 6cm

5 0
3 years ago
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