To write the equation of a line, we need 1) a point on the line 2) it's slope
For the point, we just substitute in the equation of the line intersecting it with x=3 (because they share this point)
Therefore, 2*3-3y=6 --> That gives y=0
Then the point is (x1,y1)=(3,0)
We already have the slope : m=2
Now we should use this relation for the required line equation
(y-y1) / (x-x1) = m
Then (y-0) / (x-3) = 2
Then y = 2*x - 6
And that is the required form
where 2 is the slope and -6 is the intercept
Answer:
Given point (5,-12) falls into IV quadrant
<u>The right triangle with legs of 5 and -12, and hypotenuse is:</u>
- √5² + (-12)² = √25+144 = √169 = 13
<u>Value of sinθ, cosθ, and tanθ:</u>
- sin θ = -12/13
- cos θ = 5/13
- tan θ = -12/5
2/1 is the answer. Thank ya
Answer:
Yes, with what? The Picture wont show for me.
Step-by-step explanation:
Answer:
32
24
18
13.5
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