Need help please help me # 32
1 answer:
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The area of the circle by definition is given by:
For f (r) = 154:
Clearing r we have:
For f (r) = 616:
Clearing r we have:
Answer:
a reasonable domain for f (r) is:
7 <r <14
For f (r) = 154:
Clearing r we have:
For f (r) = 616:
Clearing r we have:
Answer:
a reasonable domain for f (r) is:
7 <r <14
First step is to simplify the inside of the radical. There are x's on both top and bottom of the fraction. So we subtract their exponents. x³ - x¹ = x². Because the x³ was in the denominator and it was bigger, the x² goes on the bottom.
Your new equation is:
Now, I'd suggest factoring each term to correspond with the square root.
126y⁵ = 9 · 14 · y² · y² · y
32x² = 4 · 4 · 2 · x²
9, y², and y² can be square rooted in the numerator. 4, 4, and x² in the denominator. So we pull out their square roots and place them outside of the radical. The rest stays in the radical:
Simplify to get your final answer:
It's easier to explain on paper and in person than over computer text, sadly. Hopefully you can follow along with this.
Answer:
T(9,-2)
Step-by-step explanation:
The circle has radius 5 units and center P(6,1).
The equation of this circle is
If Q(1,11) lies on this circle, then it must satisfy its equation.
, this statement is false.
If R(2,4) lies on this circle, then it must satisfy its equation.
, this statement is false.
If S(4,-4) lies on this circle, then it must satisfy its equation.
, this statement is false.
If T(9,-2) lies on this circle, then it must satisfy its equation.
, this statement is TRUE.
The correct answer is D