Answer:
<u>the frequency</u> is the number of times a particular value occurs in a given data.
X=y-4 Let's make this eqn 1 and
2x-5y=3 this eqn 2..
Two things are possible here...
Its either you substitute for x in equation 2... Or you substitute for y...
x=y-4 put this in the equation 2..
2x-5y=3.. Replace the x with (y-4)
2(y-4)-5y = 3...
Since this is In the option no point in substituting for y...
Hope this helped...?
Answer:
The volume of the water in the pool is 1,017 cubic feet
Step-by-step explanation:
we know that
The volume of a cylinder is equal to

we have
----> the radius is half the diameter
Remember that

so

To find out the height of the water, subtract 0.5 feet from the height of the swimming pool

assume

Find the volume of the water


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Hello!
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❖ 16 min : 28 min simplified to a fraction is 
16 and 28 can both be divided by 24:
16 ÷ 4 = 4
28 ÷ 4 = 7
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Answer:
-5/4
Step-by-step explanation:
the slope is the variable in front of x
y = mx + b
m = slope
b = y-int