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goldfiish [28.3K]
3 years ago
5

Can you simplify 846/1000

Mathematics
2 answers:
OverLord2011 [107]3 years ago
8 0
Yes, the simplified fraction would 423/500
Sladkaya [172]3 years ago
6 0
423/500 that's 846/1000 simplified
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Read 2 more answers
Please help! I get how to do the first part I just don't get how to do the second part.
xz_007 [3.2K]

9514 1404 393

Answer:

  WX = 33

  (x, y) = (2, 10)

Step-by-step explanation:

The hash marks tell you WX is a midline, so has the measure of the average of the two bases.

  WX = (PQ +SR)/2 = (27 +39)/2 = 66/2

  WX = 33

__

The hash marks also tell you ...

  PW = WS

  y +4x = 18 . . . . . . substitute the given expressions

and also

  QX = XR

  2y +x = 22 . . . . . substitute the given expressions

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If you solve the first equation for y, you get ...

  y = 18 -4x

Substituting that into the second equation gives ...

  2(18-4x) +x = 22

  36 -7x = 22 . . . . . . . simplify

  14 = 7x . . . . . . . . . . . add 7x-22 to both sides

  2 = x . . . . . . . . . . . . divide by 7

  y = 18 -4(2) = 10 . . . find y using the above relation

The values of x and y are 2 and 10, respectively.

__

My favorite "quick and dirty" way to solve a set of linear equations is using a graphing calculator. It works well for integer solutions.

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3 years ago
What is the equation of a line parallel to y=1/2×+6 that passes through (-4,1)
IgorC [24]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{2}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line whose slope is 1/2 and passes through (-4 , 1)

(\stackrel{x_1}{-4}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{ \cfrac{1}{2}}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-1=\cfrac{1}{2}(x+4)\implies y-1=\cfrac{1}{2}x+2\implies y=\cfrac{1}{2}x+3

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2 years ago
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