Can you simplify 846/1000
2 answers:
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Suppose that some value, c, is a point of a local minimum point.
The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.
This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then:
As h approaches 0 from the positive side, then:
Thus, f'(c) = 0
The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.
This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then:
As h approaches 0 from the positive side, then:
Thus, f'(c) = 0
The equation is actually 
. Free fall is always -16t^2 as the position function. We are looking for how long it takes the object to hit the ground. In other words, the height of an object is 0 when it is laying on the ground, so how long (t) did it take to get there? We will then set that position equal to 0 and solve for t. 
. If we subtract 1437 from both sides and divide by -16, we have 
. Taking the square root of both sides gives us, rounded to the nearest tenth, t = 9.5 or t=-9.5. The 2 things in math that will never EVER be negative are time and distance/length, so -9.5 is out. That means that it took just about 9.5 seconds for the object to fall to the ground from a height of 1437 feet when pulled on by the force of gravity.