Answer:
The zeros are x1=4.45 and x2=-0.45.
x1 is between 4 and 5.
x2 is between -1 and 0.
Step-by-step explanation:
We have the function:

As this is a quadratic function, we can calculate the zeros of the function with the quadratic equation:

The zeros are x1=4.45 and x2=-0.45.
x1 is between 4 and 5.
x2 is between -1 and 0.
(x^2+3x^2-10x-24)/(x+2)
(4x^2-10x-24)/(x+2)
4x^2-10x-24=0
2x^2-5x-12=0
2x^2-5x-12/(x+2)
2x=(2x^2-5x)-(2x^2+4x)>>-9x-12
2x-9=(-9x-12)-(-9x-18)
2x-9=6
4x-18=12>>4x-6
(x-4)(2x+3) is the factorization
The corresponding angle is A and D and Q and R
ANSWER

EXPLANATION
We want to find the absolute value function for the line in blue.
The general form of an absolute value function is:

where (h, k) = vertex
From the line, the vertex of the graph in blue is:

To find a, we have to pick a point (x, y) on the line and input it into the general function.
Let us pick (2, 1).
Therefore, we have:

Therefore, the absolute value function is:
You would start out with multiplying giving you 5(x+6). then you would have a product of 5x+30. hoped this helped!