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dem82 [27]
3 years ago
9

Two transversals intersect two parallel lines as shown

Mathematics
1 answer:
4vir4ik [10]3 years ago
6 0

Answer:

Step-by-step explanation:

a)  Two lines are parallel and KN is transversal.

So, alternate interior angles are equal.

∠LNM =∠JKL

6x + 1 = 25

Subtract 1 from both sides.

6x + 1 - 1 = 25 -1

6x = 24

Divide both sides by 6

6x/6 = 24/6

x = 4°

b) ∠LMN = 3x +11

              = 3*4 + 11

               = 12 + 11

∠LMN = 23°

c)  ∠KJL = ∠LMN    {Alternate interior angles are equal, transversal JM}

∠KJL = 23°

In ΔKLJ,

∠JKL + ∠KLM + ∠LJK = 180°

25 + ∠KLM + 23 = 180

∠KLM + 48 = 180

∠KLM = 180 - 48

∠KLM = 132°

d) In ΔJKL & ΔLMN

∠J = ∠M

∠K=∠N

∠NLM = ∠KLJ     {Vertically opposite angles.

ΔKJL & ΔLMN  are similar triangles

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3 years ago
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Ivahew [28]
Yay, love these ones.

First of all, (4x-+3)(-2x-5) is the same as (4x-3)(-2x-5)
So the method for solving these can be remembered by FOIL.
F= Firsts   O= Outsides   I= Insides   L= Lasts

In other words everything is multiplied by everything, for example:
4x * -2x and -3 * -5 <span>is the firsts of the brackets multiplied and last of the brackets mulitplied
</span>
4x * -5 and 3 * -2x is the outsides of the brackets multiplied and the insides of the brackets multiplied
<span>
The SUM of FOIL is then added:</span><span>
</span><em>4x*-2x = -8x^2</em>
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So then you graph that equation on your given grid


</span>
8 0
3 years ago
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