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Fantom [35]
2 years ago
13

Based only on the given information, it is guaranteed that AB L CDGiven AABCAD BDBCCDs CDA. True

Mathematics
2 answers:
serious [3.7K]2 years ago
7 0
Hello,

any point equidistant from the ends of a segment belongs to the perpendicular bisector of the segment.
|AD|=|BD| and |AC|=|BC|


lys-0071 [83]2 years ago
6 0

Answer:

Option A. True.

Step-by-step explanation:

It is given in the triangle ABC

AD ≅ BD

AC ≅ BC

CD ≅ CD

By there facts Δ ADC ≅ ΔBDC

Therefore, ∠ADC ≅ ∠BDC

Since ∠ADC + ∠BDC = 180°     [Angle on a straight line AB at point D]

and ∠ADC ≅ ∠BDC

so  ∠ ADC + ∠ADC = 180°

     2∠ADC = 180°

      ∠ADC = 90°

Therefore, AB is perpendicular to DC.

Hence, option A true is the answer.

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Solve for x and y matrix
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Answer:

x=-1

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Step-by-step explanation:

\begin{pmatrix}x&y\\ \:-1&4\end{pmatrix}\begin{pmatrix}2&5\\ \:4&1\end{pmatrix}=\begin{pmatrix}18&0\\ \:14&-1\end{pmatrix}

\begin{pmatrix}x&y\\ -1&4\end{pmatrix}\begin{pmatrix}2&5\\ 4&1\end{pmatrix}

=\begin{pmatrix}x\times \:2+y\times \:4&5x+y\\ 14&-1\end{pmatrix}

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<u>OAmalOHopeO</u>

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