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Fantom [35]
3 years ago
13

Based only on the given information, it is guaranteed that AB L CDGiven AABCAD BDBCCDs CDA. True

Mathematics
2 answers:
serious [3.7K]3 years ago
7 0
Hello,

any point equidistant from the ends of a segment belongs to the perpendicular bisector of the segment.
|AD|=|BD| and |AC|=|BC|


lys-0071 [83]3 years ago
6 0

Answer:

Option A. True.

Step-by-step explanation:

It is given in the triangle ABC

AD ≅ BD

AC ≅ BC

CD ≅ CD

By there facts Δ ADC ≅ ΔBDC

Therefore, ∠ADC ≅ ∠BDC

Since ∠ADC + ∠BDC = 180°     [Angle on a straight line AB at point D]

and ∠ADC ≅ ∠BDC

so  ∠ ADC + ∠ADC = 180°

     2∠ADC = 180°

      ∠ADC = 90°

Therefore, AB is perpendicular to DC.

Hence, option A true is the answer.

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KiRa [710]
58=7/4x
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Hope this helps :)
4 0
4 years ago
I need a little help here please make it right :(
IRINA_888 [86]

Answer:

-3 X 7= -21

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Solve for y, then find the value of y when given x= -2
8090 [49]
Your answer will be c.


7 0
3 years ago
I WILL GIVE BRAINLIEST!!!
GREYUIT [131]

Answer:

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I hope this helps!

7 0
3 years ago
If AB vector =(4 5) and PQ vector=(2p 10) are parallel to each other, find the value of p.​
Sedaia [141]

Answer:

Answer:

They both have q+3/2p, so that means that 2PQ=CB and that means they are parallel to each other

Step-by-step explanation:

PQ=PA+QA

PQ=1/2(2q-p)+2/5*5p=q-1/2p+2p=q+3/2p

CB=2q+3p=2(q+3/2p)

Other explanation: It should be written like this PQ=q+3/2p and CB=2q+3p=2(q+3/2p) they are parallel bcs CB=2*PQ.

8 0
3 years ago
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