Answer:
146.9
Step-by-step explanation:
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Chloe’s 5 ft 4 inches tall. There are 2.54 centimeters in 1 inch . What is Chloe’s height in centimeters ?
2 answers:
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The expression can be used to find the coordinate of Point B. Option C is correct.
Given that,
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B is to be determined.
The equation is the relationship between variables and represented as y = ax +c is an example of a polynomial equation.
Let the coordinates of B be (x, y)
Now the distance between A (6, 5) and B (x, y) is c = 5 units
So, by the distance formula, the distance between two points is given as,
now put the value in the formula.
Thus, expression can be used to find the coordinate of Point B. Option C is correct.
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Solution
Hypotheses:
- The population mean is 132. In order to test the claim that the mean is 132, we should check for if the mean is not 132.
- Thus, the Hypotheses are:
Test statistic:
- The test statistic has to be a t-statistic because the sample size (n) is less than 30.
- The formula for finding the t-statistic is:
- Applying the formula, we have:
Critical value:
- The critical value t-critical, is gotten by reading off the t-distribution table.
- For this, we need the degrees of freedom (df) which is gotten by the formula:
- And then we also use the significance level of 0.1 and the fact that it is a two-tailed test to trace out the t-critical. (Note: significance level of 0.1 implies 10% significance level)
- This is done below:
- The critical value is 1.729
P-value:
- To find the p-value, we simply check the table for where the t-statistic falls.
- The t-statistic given is 1.5747. We simply check which values this falls between in the t-distribution table. It falls between 1.328 and 1.729. We can simply choose a value between 0.1 and 0.05 and multiply the result by 2 since it is a two-tailed test.
- However, we can also use a t-distribution calculator, we have:
- Thus, the p-value is 0.13183
Final Conclusion:
- The p-value is 0.13183, and comparing this to the significance level of 0.1, we can see that 0.13183 is outside the rejection region.
- Thus, the result is not significant and we fail to reject the null hypothesis
