Answer:
The triangles are congruent by
SSS
Step-by-step explanation:
Given:
First Label the Diagram:
AB ≅ CD
AD ≅ BC
To Prove:
Δ ABC ≅ Δ CDA
Proof:
In Δ ABC and Δ CDA
AB ≅ CD ....……….{Given}
BC ≅ DA …………..{Given}
AC ≅ AC ……….{Reflexive Property}
Δ ABC ≅ Δ CDA ….{ By Side-Side-Side test}
48m^5n: 3*2^4*m^5n
81m^2n^2: 3^4m^2n^2
GCF: 3*m^2n
Ok, so
Quadrants are found on coordinate planes. So the first number tells you to go on the X axis. It goes this way ---------
you look on the left side side of the origin (zero) and go to -5
since the second umber will be found on the Y axis, and is positive, go up to 4.
That is how you find your point. The qudrants are counted like this.
2 1
3 4
The answer is Quadrant 2
Hope it helped☺
<h2>
Answer: <u><em>
1</em></u></h2>
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Step-by-step explanation:
![\sqrt[4]{81} -2\\=3-2 \\=1](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B81%7D%20-2%5C%5C%3D3-2%20%5C%5C%3D1)