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Dvinal [7]
3 years ago
5

Which of the following is a polynomial with roots 4, 2i, and −2i?

Mathematics
2 answers:
ivolga24 [154]3 years ago
3 0
Hello,

(x+2i)(x-2i)(x-4)=(x²+4)(x-4)=x^3-4x²+4x-16

Answer C
maks197457 [2]3 years ago
3 0
X = 4; x = 2i; x = -2i

f(x) = (x - 4)(x - 2i)[x - (-2i)] = (x - 4)\underbrace{(x-2i)(x+2i)}_{a^2-b^2=(a-b)(a+b)}\\\\=(x-4)[x^2-(2i)^2]=(x-4)(x^2-2^2i^2)=(x-4)[x^2-4(-1)]\\\\=(x-4)(x^2+4)=(x)(x^2)+(x)(4)-(4)(x^2)-(4)(4)\\\\=x^3+4x-4x^2-16=\boxed{x^3-4x^2+4x-16}


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