Answer:
When t=10, the town is predicted to have around 443 acres of wetlands.
At one time, the town had 740 acres of wetlands.
The wetland area in the town decreases by 5% per year.
Step-by-step explanation:
Given

Required
The true statements

We have:

Substitute 10 for t


<em>Hence, (a) is true</em>

We have:

Substitute 740 for f(t)

Divide through by 740

Express 1 as 0.95^0

Cancel out the bases


Hence, the area had 740 acres initially;
(b) is true

We have:

Using the general formula

By comparison:

0.95 < 1 means that:
--- where r = rates

Collect like terms


Express as percentage

Hence, (c) is true

In (a)

Hence, (d) is false

In (c)
---- decrement
Hence, (e) is incorrect
Answer:
The answer will be A k>-38
180x^2+162x+10
Please mark me brainless
Move the decimal point one to the right on both sides so it would be 70/203. After that you can divide it by adding more 0s to 70. Like, 70.00 until you get an answer
• 4y = -2x + 11
• y = -2/4x + 11/4
• y = -1/2x + 11/4