What’s the fifth term of a sequence whose first term is 5 and whose common ratio is 3?
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8 goes in to 16 2 times so put 2 on the top. 8 x 2 is 16 so do 16 - 16 which is 0. 8 cant go into 0 so put a 0 on top. Bring down the 1; 8 cant go into 1 so bring down the 3. 8 can go into 13 1 time so put a 1 on top. 13 - 8 is 5 so the remainder is 5
