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Alla [95]
3 years ago
9

A man weighing 340 pounds is admitted into a hospital for a special diet to lose no more than 6 pounds per week. What is the sho

rtest time in weeks it could take the man to reduce his weight to 243 pounds?
Mathematics
2 answers:
Sauron [17]3 years ago
7 0

Answer:

Step-by-step explanation:

340-243 =97

97/6 = 16

16 weeks to lose 6 pounds per week.

OLEGan [10]3 years ago
5 0

Answer:

Let's think.

If we want the man to be in the best case scenario in which he loses the most pounds that his limit lets him, we should always make the man lose the highest he could go: 6 pounds.

This is just a simple multi step problem if you break it down.

If his goal is to get to 243 pounds, we firstly subtract 243 from 340 to see how much he needs to lose.

340 - 243 = 97

The man wants to lose 97 pounds.

Let's divide this number by 6 with remainder.

I'll let you think for a bit.

97 / 6 = 16 remainder 1.

This means that in 16 weeks, he needs to lose 6 pounds while on the 17th week, he needs to lose 1 pound.

I'm sorry if i misunderstood.

Good luck Mate :)

Don't forget to try everyday !

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Answer:

(See step-by-step)

Step-by-step explanation:

Let’s start by making A-(X) and W-(Y). So, when substituting the variables you get x=210-35y. When x=0, the answer to the equation is 6. So, the y-intercept (when x=0) is 6 or (0,6). When y=0, the answer to the equation/x-intercept(y=0) is 210 or (210,0). The graph itself looks like the image included.

The domain, realistically, is x>=0 however on the graph itself, the domain is x= All Real Numbers. The range realistically is y>=0, but on the graph it is also All Real Numbers.  

The x-intercept is the account when no weeks have passed and no money is lost (210) and the y-intercept is the maximum amount of weeks before there is no more money in the account (6).  

3 0
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4 0
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In the figure, what is the value of x?
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Answer:

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3 0
3 years ago
HEY CAN ANYONE HELP ME!
nataly862011 [7]

Answer:

Given: In triangle ABC and triangle DBE where DE is parallel to AC.

In ΔABC and ΔDBE

DE || AC   [Given]

As we know, a line that cuts across two or more parallel lines.  In the given figure, the line AB is a transversal.

Line segment  AB is transversal that intersects two parallel lines.  [Conclusion from statement 1.]

Corresponding angles theorem: two parallel lines are cut by a transversal, then the  corresponding angles are congruent.

then;

\angle BDE \cong \angle BAC  and

\angle BEC \cong \angle BCA

Reflexive property of equality states that if angles in geometric figures can be congruent to themselves.

by Reflexive property of equality:

\angle B \cong \angle B  

By AAA (Angle Angle Angle) similarity postulates states that all three pairs of corresponding angles are the same then, the triangles are similar

therefore, by AAA similarity postulates theorem

\triangle ABC \sim \triangle DBE

Similar triangles are triangles with equal corresponding angles and proportionate side.

then, we have;

\frac{BD}{BA}                  [By definition of similar triangles]

therefore, the missing statement and the reasons are

Statement                                                                   Reason

3.\angle BDE \cong \angle BAC      Corresponding angles theorem

and  \angle BEC \cong \angle BCA        

5. \triangle ABC \sim \triangle DBE   AAA similarity postulates    

6. BD over BA                                                    Definition of similar triangle



7 0
3 years ago
Read 2 more answers
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