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3 years ago

Albert is 4 times older than his son how old is he?

Mathematics

1 answer:

Artemon [7]3 years ago

7 0

Answer:

Step-by-step explanation:

You don't really have enough information to answer this question, thank you Because like you don't know how old Albert son is they can't figure out how old Albert is without knowing how old his son is.

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Please help problem below 15 POINTS!!

solniwko [45]

$i=\frac{12*1.9x^{x} }{x}$

3 0

4 years ago

Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the sq

stiv31 [10]

Answer:

Step-by-step explanation:

Remark

This is one of those questions that can throw you. The problem is that do you include the original rectangle or not. The way it is written it sounds like you shouldn't

However if you don't the question gives you 2 complex answers. (answers with the sqrt( - 1) in them.

Solution

Let the width = x

Let the length = x + 5

Area of the rectangle: L * w = x * (x + 5)

Area of the smaller squares (there are 2)

Area = 2*s^2

x = s

Area = 2 * x^2

Area of the larger squares = 2 * (x+5)^2

Total Area

x*(x + 5) + 2x^2 + 2(x + 5)^2 = 120 Expand

x^2 + 5x + 2x^2 + 2(x^2 + 10x + 25) = 120 Remove the brackets

x^2 + 5x + 2x^2 + 2x^2 + 20x + 50 = 120 collect the like terms on the left

5x^2 + 25x + 50 = 120 Subtract 120 from both sides.

5x^2 + 25x - 70 = 0 Divide through by 5

x^2 + 5x - 14 = 0 Factor

(x + 7)(x - 2) = 0 x + 7 has no meaning

x - 2 = 0

x = 2

Perimeter

P = 2*w + 2*L

w = 2

L = 2 + 5

L = 7

P = 2*2 + 2 * 7

P = 4 + 14

P = 18

8 0

3 years ago

If a 30 foot ladder is positioned so that the bottom of the ladder is 1/4 of its length away from the wall, how far up the wall

Dvinal [7]

Answer:

29.05 ft

Step-by-step explanation:

Using the concept of pythagoras theorem, here we have the base and hypotenuse given hence we need to find the third dimension, assuming the wall is perfectly straight and forms a right angle with the bsse of the ladder. Here, $c^{2}=a^{2}+b^{2}$ and making a the subject of the formula then $a=\sqrt {c^{2}-b^{2}}$ and substituting 30 ft for c and 0.25*30=7.5 ft for b then $a=\sqrt {30^{2}-7.5^{2}}=\sqrt {843.75}=29.047375096555626\approx 29.05 ft$